Merge Intervals
Medium
Subject: Intervals
Time Complexity
O(N log N)
Space Complexity
O(N)
Problem Description
Given an array of intervals where intervals[i] = [start_i, end_i], merge all overlapping intervals and return an array of the non-overlapping intervals that cover all the intervals in the input.
Optimal Solution
Pythondef merge(intervals):
intervals.sort(key=lambda x: x[0])
merged = [intervals[0]]
for start, end in intervals[1:]:
last_end = merged[-1][1]
if start <= last_end:
merged[-1][1] = max(last_end, end)
else:
merged.append([start, end])
return merged